Parallel, Perpendicular and Intersecting lines are three types of lines based on their properties. This article provide worksheet for practice of questions based on parallel, perpendicular and intersecting lines. This article also contain, formula and solved examples to make you understand how to solve the worksheet

## Parallel, Perpendicular and Intersecting Lines Formulas

The formulas of useful for parallel, perpendicular and intersecting lines are mentioned below:

Slope Formula

:

- The slope (m) of a line passing through points (x1, y1) and (x2, y2) is given by:
- m = (y
_{2}β y_{1})/(x_{2}β x_{1})Parallel Lines

:

- Two lines are parallel if and only if their slopes are equal. That is, if two lines have slopes m
_{1}and m_{2}- They are parallel if m
_{1}= m_{2}Perpendicular Lines

:

- Two lines are perpendicular if the product of their slopes is -1. That is, if two lines have slopes m1 and m2
- They are perpendicular if m
_{1}Γ m_{2}= β1.Intersecting Lines

:

- Intersecting lines has unique solution
- The intersection point of two lines can be found by solving their equations simultaneously.

## Practice Questions with Solution

### Q1: Determine if the lines y = 2x + 3 and y = 2x β 4 are parallel, perpendicular, or neither.

**Solution:**

To determine if two lines are parallel, perpendicular, or neither, we can look at their slopes.

The slope of a line in the form y = mx + b is m.

For the line y = 2x + 3, the slope is m=2.

For the line y = 2x β 4, the slope is also m=2.

Since both lines have the same slope of 2, they are parallel.

### Q2: Find the equation of the line passing through the point (3, 5) and parallel to the line 2x β 3y = 6.

**Solution:**

To find the equation of a line passing through the point (3, 5) and parallel to the line 2x β 3y = 6, we need to find the slope of the given line and then use this slope to construct the equation of the parallel line.

First, we rearrange the equation of the given line into slope-intercept form (y = mx + b)

2x β 3y = 6

β3y = β2x + 6

y = 2/3x β 2

The slope of this line is m= 2/3.

Since the line we want to find is parallel to this line, it will have the same slope. So, the slope of the parallel line is also m = 2/3.

Now, we can use the point-slope form of the equation of a line to find the equation of the parallel line:

y β y

_{1}= m(x β x_{1})where (x1, y1) is the given point (3, 5) and m is the slope 2/3

Substituting

x1 = 3, y1 = 5, and m = 2/3 , we get:

y β 5 = 2/3(x β 3)

Now, we can simplify this equation to obtain the final form:

y β 5 = 2/3(x β 3)

y = 2/3x β 2 + 5

So, the equation of the line passing through the point (3, 5) and parallel to the line 2x β 3y = 6 is y = 2/3x + 3.

### Q3: Determine if the lines 3x + 2y = 8 and 6x + 4y = 10 are parallel, perpendicular, or neither.

**Solution:**

To determine if two lines are parallel, perpendicular, or neither, we can compare their slopes.

First, letβs rearrange both equations into slope-intercept form (y = mx + b):

For 3x + 2y = 8

2y = β3x + 8

y = β3/2x + 4

For 6x + 4y = 10

4y = β6x + 10

y = β3/2x + 5/2

Comparing the slopes of both lines, we see that both lines have the same slope, which is β3/2.

Since both lines have the same slope, they are parallel.

### Q4: Find the equation of the line perpendicular to y = 4x β 1 passing through the point (2, β3).

**Solution:**

To find the equation of the line perpendicular to

y = 4x β 1 passing through the point (2, β3), we first need to determine the slope of the given line.

The given line is in the slope-intercept form

y = mx + b, where

m is the slope. In this case, the slope of the given line is m=4.

The slope of any line perpendicular to this line will be the negative reciprocal of 4. So, the slope of the perpendicular line will be -1/4

Now, we can use the point-slope form of a line to find the equation of the perpendicular line. The point-slope form of a line is

y β y

_{1}= m(x β x_{1}),where (x1, y1) is a point on the line and m is the slope.

We are given a point (2, β3) on the perpendicular line, and the slope m = β1/4. Substituting these values into the point-slope form, we get: y β (β3) = β1/4(x β 2)

Simplify: y + 3 = β 1/4x + 1/2

Now, we can rewrite this equation in slope-intercept form by isolating y:

y = β1/4x + 1/2 β 3

y = β1/4x β 5/2

So, the equation of the line perpendicular to y = 4x β 1 passing through the point (2, β3) is y = β1/4x β 5/2.

### Q5: Determine if the lines 2x β 3y = 5 and 6x β 9y = 15 are parallel, perpendicular, or neither.

**Solution:**

To determine if two lines are parallel, perpendicular, or neither, we can examine their slopes.

The slope-intercept form of a line is y = mx + b, where m is the slope of the line.

For the first line 2x β 3y = 5, letβs rewrite it in slope-intercept form:

3y = 2x β 5

y= 2/3x β 5/3

So, the slope of the first line is m1 = 2/3

For the second line 6x β 9y = 15, letβs rewrite it in slope-intercept form:

9y = 6x β 15

y = 2/3x β 5/3

So, the slope of the second line is m2 = 2/3

Since the slopes of both lines are equal (m1 = m2 = 2/3), the lines are parallel.

So, the lines 2x β 3y = 5 and 6x β 9y = 15 are parallel.

### Q6: Find the point of intersection of the lines y = 2x β 1 and y = β3x + 7.

**Solution:**

To find the point of intersection of the two lines, we need to set their equations equal to each other and solve for the value of x.

So, we have: 2x β 1 = β3x + 7

Now, letβs solve for x:

2x + 3x = 7 + 1

5x = 8

x = 8/5

Now that we have found x, letβs substitute it back into one of the equations to find the corresponding y value. Letβs use the first equation:

y = 2(8/5) β 1

y = 16/5 β1

y = 16/5 β 5/5

y = 16β5/5

y = 11/5

So, the point of intersection of the lines y = 2x β 1 and y = β3x + 7 is (8/5, 11/5).

### Q7. Determine if the lines 4x + 2y = 6 and 8x + 4y = 12 are parallel, perpendicular, or neither.

**Solution:**

To determine if two lines are parallel, perpendicular, or neither, we can examine their slopes.

The slope-intercept form of a line is y = mx + b, where m is the slope of the line.

For the first line 4x + 2y = 6, letβs rewrite it in slope-intercept form:

2y = β4x + 6

y = β2x + 3

So, the slope of the first line is m1 =β2.

For the second line 8x + 4y = 12, letβs rewrite it in slope-intercept form:

4y = β8x + 12

y = β2x + 3

So, the slope of the second line is m2 = β2.

Since the slopes of both lines are equal (m1 = m2 = β2), the lines are parallel.

So, the lines 4x + 2y = 6 and 8x + 4y = 12 are parallel.

### Q8. Find the intersection point of the lines 3x + 2y = 8 and 2x β 4y = 5.

**Solution:**

To find the intersection point of two lines, you need to solve the system of equations formed by the equations of the lines. Letβs solve the system of equations

3x + 2y = 8

2x β 4y = 5

We can solve this system by either substitution or elimination method. Letβs use the elimination method.

Multiply the first equation by 2 and the second equation by 3 to eliminate y:

6x + 4y = 16

6x β 12y = 15

Now, subtract the second equation from the first equation:

(6x + 4y) β (6x β 12y) = 16 β 15

6x + 4y β 6x + 12y = 1

16y = 1

Now, solve for y: y = 1/16

Now, substitute y back into one of the original equations to solve for x. Letβs use the first equation

3x + 2(1/16) = 8

3x + 1/8 = 8

3x = 8 β 1/8

3x = 64/8 β 1/8

3x= 63/8

x = 63/24

So, the intersection point of the lines 3x + 2y = 8 and 2x β 4y = 5 is (x, y) = (63/24, 1/16)

### Q9. Determine the intersection point of the lines y = 2x + 1 and y = β3x + 5.

**Solution:**

To find the intersection point of two lines, you need to set their equations equal to each other and solve for the values of x and y.

Given the equations:

y = 2x + 1

y = β3x + 5

Setting them equal to each other:

2x + 1 = β3x + 5

Now, solve for x:

2x + 3x = 5β1

5x = 4

x= 4/5

Now that we have found the value of x, we can substitute it into either equation to find the corresponding y-coordinate. Letβs use the first equation:

y = 2(4/5) + 1

y = 8/5 + 1

y = 8/5 + 5/5

y = 13/5

So, the intersection point of the lines y = 2x + 1 and y = β3x + 5 is (4/5, 13/5).

### Q10. Determine if the lines 2x + 3y = 7 and 4x + 6y = 14 are parallel, perpendicular, or neither.

**Solution:**

To determine if the lines 2x + 3y = 7 and 4x + 6y = 14 are parallel, perpendicular, or neither, we can compare their slopes.

First, weβll rewrite the equations in slope-intercept form (y = mx + b) where m represents the slope:

For 2x + 3y = 7

3y = β2x + 7

y = β2/3x + 7/3

So, the slope of this line is m1 = β2/3

For 4x + 6y = 14

6y = β4x + 14

y = β4/6x + 14/6

y = β2/3x + 7/3

So, the slope of this line is m2 = β2/3.

Since the slopes of both lines are identical (m1 = m2 = β2/3), the lines are parallel.

Therefore, the lines 2x + 3y = 7 and 4x + 6y = 14 are parallel.

## Parallel, Perpendicular and Intersecting Lines Worksheets

Q1: Determine if the lines y = 3x + 2 and y = 3x β 4 are parallel, perpendicular, or neither.

Q2: Find the equation of the line passing through the point (4, 6) and parallel to the line 3x β 4y = 7.

Q3: Determine if the lines 2x + 5y = 10 and 4x + 10y = 15 are parallel, perpendicular, or neither.

Q4: Find the equation of the line perpendicular to y = 2/3x β 4 passing through the point (β1, 2).

Q5: Determine if the lines 5x β 2y = 8 and 10x β 4y = 16 are parallel, perpendicular, or neither.

Q6: Find the point of intersection of the lines y = β1/2x + 3 and y = 2x β 1.

Q7: Determine if the lines 6x + 3y = 9 and 9x + 4y = 12 are parallel, perpendicular, or neither.

Q8: Find the intersection point of the lines 4x + 5y = 17 and 3x β 2y = 11.

Q9: Determine the intersection point of the lines y = 3x β 2 and y= β2x + 7.

Q10: Determine if the lines 3x + 4y = 10 and 9x + 12y = 30 are parallel, perpendicular, or neither.

## FAQs on Parallel, Perpendicular and Intersecting Lines

### What are parallel lines?

Parallel lines are lines in a plane that are always the same distance apart and never meet, no matter how far they are extended. They have the same slope if represented in a coordinate system.

### What are perpendicular lines?

Perpendicular lines are lines that intersect at a right angle (90 degrees). In a coordinate system, the slopes of two perpendicular lines are negative reciprocals of each other (i.e., if one line has a slope of m, the other line will have a slope of β1/mβ).

### What are intersecting lines?

Intersecting lines are lines that meet or cross at one point. Unlike parallel lines, intersecting lines have different slopes unless they are the same line (coincident).

### What is the significance of the slopes in determining the relationship between lines?

The slope of a line indicates its steepness and direction. Comparing the slopes of two lines helps determine their relationship:

: The lines are parallel.Same slope: The lines are perpendicular.Negative reciprocal slopes: The lines will intersect at some point unless they are parallelDifferent slopes

### Can two lines be both parallel and perpendicular?

No, two lines cannot be both parallel and perpendicular. Parallel lines never intersect and have the same slope, while perpendicular lines intersect at a right angle and have slopes that are negative reciprocals of each other.

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